How do you solve $| x + 3 | = | 6 x + 9 |$ $abs(x+3)=abs(6x+9)$ ?

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Answer 1 · 2016-04-17T20:50:49

$- \frac{6}{5}$ $-6/5$ and $- \frac{12}{7}$ $-12/7$

Or the expressions inside the brachets are equal, or they are symmetric:

$| x + 3 | = | 6 x + 9 |$ $|x+3|=|6x+9|$

1) $x + 3 = 6 x + 9$ $x+3=6x+9$

$- 5 x = 6$ $-5x=6$

#x=-6/5

2) $x + 3 = - (6 x + 9)$ $x+3=-(6x+9)$

$x + 3 = - 6 x - 9)$ $x+3=-6x-9)$

$7 x = - 12$ $7x=-12$

$x = - \frac{12}{7}$ $x=-12/7$

How do you solve |x+3|=|6x+9|abs(x+3)=abs(6x+9)?