How do you solve $| y - 8 | + 6 = 15$ $abs(y - 8) +6 =15$ ?

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Answer 1 · 2015-04-29T11:52:08

$| y - 8 | + 6 = 15$ $abs(y-8) + 6 = 15$
is equivalent to
$| y - 8 | = 9$ $abs(y-8) = 9$

If $(y - 8)$ $(y-8)$ is negative this is equivalent to
$8 - y = 9$ $8-y = 9$
$y = - 1$ $y=-1$

If $(y - 8) \geq 0$ $(y-8)>=0$ this is equivalent to
$y - 8 = 9$ $y-8=9$
$y = 17$ $y=17$

So $y ε {- 1, 17}$ $y epsilon {-1,17}$

How do you solve abs(y - 8) +6 =15|y−8|+6=15 abs(y - 8) +6 =15?