How do you solve and check your solutions to $- 4 q = 52$ $-4q=52$ ?

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Answer 1 · 2016-10-07T15:19:19

$q = - 13$ $q=-13$

Given: $- 4 q = 52$ $" "color(brown)(-4q=52)$

Divide both sides by $4$ $color(blue)( 4)$

$- \frac{4}{4} \times q = \frac{52}{4}$ $color(brown)(-4/(color(blue)(4)) xx q=52/(color(blue)(4)))$

But $- \frac{4}{4} = - 1$ $-4/4=-1$

$- 1 \times q = 13$ $-1xxq= 13$

$- q = 13$ $-q=13$

Multiply both sides by $(- 1)$ $(-1)$ giving

$+ q = - 13$ $+q=-13$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Check: Substitute $- 13$ $-13$ for $q$ $q$

$\Rightarrow - 4 q = 52 \to - 4 (- 13) = 52$ $=>color(brown)(-4q=52)" "->" "color(blue)(-4(-13)=52$

Consider the left hand side (LHS) of the equation.

Minus times minus gives plus (positive) and $4$ $4$ is the same as $2 \times 2$ $2xx2$

so $4 \times 13$ $4xx13" "$ is the same as

$2 \times 2 \times 13 \to 2 \times 26 \to 52 \to L H S$ $" "2xx2xx13 -> 2xx26->52 -> LHS$

So LHS=RHS=52

How do you solve and check your solutions to −4q=52-4q=52?