How do you solve and find the value of ${cos}^{- 1} (\frac{1}{2})$ $cos^-1 (1/2)$ ?

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Answer 1 · 2017-02-04T12:12:30

${cos}^{- 1} (\frac{1}{2}) = \frac{π}{3} = 60^{0}$ $cos^-1 (1/2) = pi/3 =60^0$

Let $cos^-1 (1/2) =x :. cos x =1/2 ; cos (pi/3) = 1/2 ; cos (2pi-pi/3)=cos ((5pi)/3)=1/2 :. x= pi/3 and x = (5pi)/3$

The range of $cos^-1$ is $[0. pi] ; x =(5pi)/3$ is out of range. $:. cos^-1 (1/2) = pi/3 =60^0$ [Ans]

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