How do you solve and find the value of $cos (arccos (- \frac{1}{2}))$ $cos(arccos(-1/2))$ ?

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How do you solve and find the value of $cos (arccos (- \frac{1}{2}))$ $cos(arccos(-1/2))$ ?

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Answer 1 · 2016-12-02T15:28:10

$- \frac{1}{2}$ $- 1/2$

Explanation:

Use trig table of special arcs and unit circle -->
$cos x = - \frac{1}{2}$ $cos x = - 1/2$ --> 2 solution arcs -->
arc $x = \frac{2 π}{3}$ $x = (2pi)/3$ and arc $x = \frac{4 π}{3}$ $x = (4pi)/3$
$cos (\frac{2 π}{3}) = cos (\frac{4 π}{3}) = - \frac{1}{2}$ $cos ((2pi)/3) = cos ((4pi)/3) = - 1/2$

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How do you solve and find the value of $cos (arccos (- \frac{1}{2}))$ $cos(arccos(-1/2))$ ?

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