How do you solve and find the value of $cos ({cos}^{- 1} (\frac{2}{9}))$ $cos(cos^-1(2/9))$ ?

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Answer 1 · 2017-02-07T11:57:04

$0.222222222$ $0.222222222$ or $\frac{2}{9}$ $2/9$

$cos ({cos}^{- 1} (\frac{2}{9}))$ $cos(cos^-1(2/9))$

$:.=cos(arccos(0.222222222)$

$:.=cos(77.16041159)rarr$ decimals of a degree $rarr77°09'37.48''$

$:.=0.222222222rarr 2/9$

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