Question

How do you solve and find the value of `sin^-1(1/2)`?

Answer 1

`pi/6 + 2kpi`
`(5pi)/6 + 2kpi`

Explanation:

`sin^-1 (1/2) --> arcsin (1/2)`
Trig table of special arcs gives -->
`sin x = 1/2` --> arc `x = pi/6`
Unit circle gives another arc that has the same sin value (1/2) -->
arc `x = pi - pi/6 = (5pi)/6`
General answers:
`x = pi/6 + 2kpi`
`x = (5pi)/6 + 2kpi`