How do you solve and find the value of ${sin}^{- 1} (\frac{π}{2})$ $sin^-1(pi/2)$ ?

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Answer 1 · 2017-07-23T09:55:48

$pi/2=1.570796...$ and is greater than one and as sine of any angle can only take values in the interval $[-1,1]$ , there is no solution.

How do you solve and find the value of sin^-1(pi/2)sin−1(π2)sin^-1(pi/2)?