How do you solve and find the value of sin(arctan(sqrt3/3))sin(arctan(33))?

1 Answer
Mar 19, 2018

color(red)(theta = n pi + pi/6 color(white)(aaa)θ=nπ+π6aaa color(green)(n in ZZ

Explanation:

Let theta = arctan(sqrt3/3)

tan theta = tan (tan^-1 (sqrt3/3))

tan theta = sqrt3 / 3 = 1/ sqrt 3

theta = pi / 6 = 30^@

Genaralozing,

theta = n pi + pi/6 color(white)(aaa) n in ZZ