How do you solve and find the value of $sin ({sin}^{- 1} (\frac{3}{4}))$ $sin(sin^-1(3/4))$ ?

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Answer 1 · 2017-03-02T16:19:45

$sin ({sin}^{- 1} (\frac{3}{4})) = \frac{3}{4}$ $sin(sin^(-1)(3/4))=3/4$

By definition if $sin A = x$ $sinA=x$ , ${sin}^{- 1} x = A$ $sin^(-1)x=A$ ,

Now let ${sin}^{- 1} (\frac{3}{4}) = x$ $sin^(-1)(3/4)=x$

$:.sinx=3/4$ and in this substituting $x$ for sin^(-1)(3/4)#

we get $sin(sin^(-1)(3/4))=3/4$

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