How do you solve and graph $-1/3<=(4x-1 )/ 3 <1/2$ ?

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Answer 1 · 2016-05-17T15:19:18

$0<=x<5/8$ .The graph is the line segment on the axis of reals, for $x in [0, 5/8)$ .

Multiply throughout by +6.

Then, $-2<2(4x-1)<3$ .

Separating the inequalities,

$-2<=8x-2 and 8x-2<3$ . Rearranging,

$x>=0 and x<5/8$ .

Now combine the inequalities.

$0<=x<5/8$ .

The graph is the line segment on the axis of reals, for $x in [0, 5/8)$ .

How do you solve and graph -1/3<=(4x-1 )/ 3 <1/2-1/3<=(4x-1 )/ 3 <1/2?