How do you solve and graph -3 ≤ 3 - 2x< 11?

1 Answer
Jul 5, 2017

See a solution process below:

Explanation:

First, subtract color(red)(3) from each segment of the system of inequalities to isolate the x term while keeping the system balanced:

-color(red)(3) - 3 <= -color(red)(3) + 3 - 2x < -color(red)(3) + 11

-6 <= 0 - 2x < 8

-6 <= -2x < 8

Now, divide each segment by color(blue)(-2) to solve for x while keeping the system balanced. However, because we are multiplying or dividing inequalities by a negative number we must reverse the inequality operators:

(-6)/color(blue)(-2) color(red)(>=) (-2x)/color(blue)(-2) color(red)(>) 8/color(blue)(-2)

3 color(red)(>=) (color(blue)(cancel(color(black)(-2)))x)/cancel(color(blue)(-2)) color(red)(>) -4

3 color(red)(>=) x color(red)(>) -4

Or

x > -4 and x <= 3

Or, in interval notation:

(-4, 3]