How do you solve and graph $- 3 \leq 3 - 2 x \leq 9$ $-3<=3-2x<=9$ ?

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Answer 1 · 2017-08-22T21:39:05

Given $- 3 \leq 3 - 2 x \leq 9$ $-3<=3-2x<=9$

Subtract 3 from left, center, and right:

$- 6 \leq - 2 x \leq 6$ $-6 <= -2x <= 6$

Multply left, center, and right by -1/2. Note: When we do this, we change every $<$ $<$ into $>$ $>$

$3 \geq x \geq - 3$ $3 >= x >= -3$

Because of symmetry, this can be written as if we had not changed them at all:

$- 3 \leq x \leq 3$ $-3<=x<=3$

How do you solve and graph −3≤3−2x≤9-3<=3-2x<=9?