How do you solve and graph $-4z+13>=29$ and $10<6a-14$ ?

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Answer 1 · 2018-04-13T18:25:59

$-4z + 13 >= 29$

isolate the variable

$-4z >= 29-13$

not that the sign changes, because we divided by a negative number

$z <= 16/-4$

$z <= -4$

graph{y <= -4}

$* * * * * * * * * * * * * * * * *$

$10<6a-14$

$10 +14 < 6a$

$24/6 < a$

$4 < a$

graph{y < 4}

How do you solve and graph -4z+13>=29-4z+13>=29 and 10<6a-1410<6a-14?