How do you solve and write the following in interval notation: #2x + 6 < 8#?

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Answer 1 · 2018-03-18T14:33:56

See a solution process below:

First subtract #color(red)(6)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:

#2x + 6 - color(red)(6) < 8 - color(red)(6)#

#2x + 0 < 2#

#2x < 2#

Now, divide each side of the inequality be #color(red)(2)# to solve for #x# while keeping the inequality balanced:

#(2x)/color(red)(2) < 2/color(red)(2)#

#(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) < 1#

#x < 1#

Or, in interval notation:

#(-oo, 1)#