Question

How do you solve `Ax=B` given `A=((2, 3))` and `B=(4)`?

Answer 1

`x=((m),((4-2m)/3))` for any value of `m`

Explanation:

If `x=((m),(n))`
then (by definition of matrix multiplication)
`color(white)("XXX")Ax = (2,3)xx((m),(n))=(2m+3n)`

and if `Ax=B=(4)`

then
`color(white)("XXX")2m+3n=4`

Simplifying
`color(white)("XXX")n=(4-2m)/3`

Note that there are infinitely many solutions for `x`
a few obvious possibilities are:
`color(white)("XXX")x=((0),(4/3)) or x=((2),(0)) or x=((5),(-2))`