How do you solve $b - 2 = - 11$ $b-2=-11$ ?

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Answer 1 · 2017-02-22T13:10:52

Add $2$ $color(red)(2)$ to each side of the equation to solve for $b$ $b$ while keeping the equation balanced:

$b - 2 + 2 = - 11 + 2$ $b - 2 + color(red)(2) = -11 + color(red)(2)$

$b - 0 = - 9$ $b - 0 = -9$

$b = - 9$ $b = -9$

How do you solve b−2=−11b-2=-11?