How do you solve by completing the square for 2x^2 - 4x + 5 = 0?

1 Answer
Jun 3, 2015

2x^2-4x+5 = 0

color(white)("XXXX")2(x^2-2x) = -5

color(white)("XXXX")2(x^2-2x+1) = -5 +2

color(white)("XXXX")(x-1)^2 = -3/2

color(white)("XXXX")x-1 = +-sqrt(-3/2)

note: there will be no Real solutions
color(white)("XXXX")x = 1+-sqrt(3/2)i