How do you solve by completing the square: $x^2+7x-5=0$ ?

Question

7256 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-04-02T16:40:56

Write it as:
$x^2+7x=5$
$x^2+7x+49/4-49/4=5$
$(x+7/2)^2=5+49/4$
$(x+7/2)^2=69/4$
$x+7/2=+-sqrt(69/4)$
$x+7/2=+-sqrt(69)/2$
$x=-7/2+-sqrt(69)/2$

How do you solve by completing the square: x^2+7x-5=0x^2+7x-5=0?