How do you solve compound inequalities #8d<-64# and #5d > 25#?

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Answer 1 · 2015-05-19T08:10:52

Let's look at each inequality individually first.

#8d<-64#

Dividing both sides by 8, we get:

#(cancel(8)d)/cancel(8) < -64/8#

#color(blue)(d < - 8#

#5d>25#

Dividing both sides by 5, we get:

#(cancel(5)d)/cancel(5) > 25/5#

#color(blue)(d>5#

#d# can take any value which is less than #-8# or greater than #5#

The values #d# will take on the number line are marked in blue. (The values #-8 and 5# are not included)

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