Question

How do you solve `d^ { 2} = 50- 23d`?

Answer 1

See below

Explanation:

We have `d^2=50-23d`, or `d^2+23d-50=0`.
By factoring the latter, we arrive at `(d+25)(d-2)=0`.
Thus, `d=-25, 2`.

For more information on how to factor polynomials, click the link below.

http://www.instructables.com/id/How-to-factor/

Answer 2

`d = 2 or -25`

Explanation:

This is a quadratic function.
First, you need to make it into a quadratic function which looks like this:

`d^2 = 50 - 23d`

Transpose

`d^2 + 23d - 50 = 0`

`{(a = 1), (b = 23), (c = -50) :}`

`ac = 1 * -50 = -50`

Two factors of `-50` that give the result of `b`, `23` are:

`-2 and 25`

So

`d^2 - 2d + 25d -50 = 0`

Factorize

`d(d - 2) + 25 (d - 2) = 0`

`(d-2) (d + 25) = 0`

`d-2= 0`

`d= 0 + 2= 2`

or

`d+25=0`

`d= 0- 25= -25`

`d= 2 or -25`