How do you solve $e^{3x - 1} = 4.96$ ?

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Answer 1 · 2017-02-28T16:34:16

$x = 0.867$

1) $e^(3x - 1) = 4.96$
2) $3x - 1 = ln(4.96)$
3) $3x = 1.601 + 1$
4) $3x = 2.601$
5) $x = 0.867$

How do you solve e^{3x - 1} = 4.96e^{3x - 1} = 4.96?