How do you solve #e^{3x - 1} = 4.96#? Precalculus Properties of Logarithmic Functions Natural Logs 1 Answer Kevin L. Feb 28, 2017 #x = 0.867# Explanation: 1) #e^(3x - 1) = 4.96# 2) #3x - 1 = ln(4.96)# 3) #3x = 1.601 + 1# 4) #3x = 2.601# 5) #x = 0.867# Answer link Related questions What is the natural log of e? What is the natural log of 2? How do I do natural logs on a TI-83? How do I find the natural log of a fraction? What is the natural log of 1? What is the natural log of infinity? Can I find the natural log of a negative number? How do I find a natural log without a calculator? How do I find the natural log of a given number by using a calculator? How do I do natural logs on a TI-84? See all questions in Natural Logs Impact of this question 1741 views around the world You can reuse this answer Creative Commons License