How do you solve ${(e^{4})}^{x} \cdot e^{x^{2}} = e^{12}$ $(e^4)^x * e^(x^2) = e^12$ ?

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Answer 1 · 2016-07-08T01:06:42

$e^{4 x} \times e^{x^{2}} = e^{12}$ $e^(4x) xx e^(x^2) = e^12$

By the rule $a^{n} \times a^{m} = a^{n + m}$ $a^n xx a^m = a^(n + m)$

$x^{2} + 4 x - 12 = 0$ $x^2 + 4x - 12 = 0$

$(x + 6) (x - 2) = 0$ $(x + 6)(x - 2) = 0$

$x = - 6 and 2$ $x = -6 and 2$

Hopefully this helps!

How do you solve (e4)x⋅ex2=e12(e^4)^x * e^(x^2) = e^12?