How do you solve $e^(-5n-1)+3.9=75$ ?

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Answer 1 · 2016-08-27T02:04:07

$e^(-5n - 1) = 75 - 3.9$

$e^(-5n - 1) = 71.1$

$-5n - 1 = ln71.1$

$-5n = ln71.1 + 1$

$n = -1.05$

Hopefully this helps!

How do you solve e^(-5n-1)+3.9=75e^(-5n-1)+3.9=75?