How do you solve $-e^(6-9p)+5=-48.4$ ?

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Answer 1 · 2016-11-27T23:34:10

$p=1/9ln53.4-2/3$

$p approx -.2247$

$-e^(6-9p)+5=-48.4$

Subtract $5$ from each side:
$-e^(6-9p)=-53.4$

Divide each side by $-1$ :
$e^(6-9p)=53.4$

Rewrite as a natural log:
$ln53.4=6-9p$

Solve for p -- subtract 6 from each side:
$ln53.4-6=9p$

Divide each side by 9:
$frac{ln53.4-6}{9}=p$

Simplify:
$p=1/9ln53.4-2/3$

How do you solve -e^(6-9p)+5=-48.4-e^(6-9p)+5=-48.4?