How do you solve $e^{ln x} = 21$ $e^ { \ln x } = 21$ ?

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Answer 1 · 2018-04-17T05:19:10

x=21, e $e^{ln x} = x$ $e^(lnx) = x$

x=21, e $e^{ln x} = x$ $e^(lnx) = x$ by the rules of logarithms and exponential funcs

Answer 2 · 2018-04-17T05:21:48

$x = 21$ $x=21$

Given: $e^{ln x} = 21$ $e^(lnx)=21$

Notice that $e^{ln x} = x$ $e^(lnx)=x$ .

So, we get: $x = 21$ $x=21$

How do you solve elnx=21e^ { \ln x } = 21?