How do you solve $e^{ln x} = 4$ $e^lnx=4$ ?

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Answer 1 · 2016-04-09T05:14:10

$x = 4$ $x=4$

We know that $ln a$ $lna$ means ${log}_{e} a$ $log_ea$

As $e^{ln x} = 4$ $e^lnx=4$ , $ln x = ln 4$ $lnx=ln4$

and hence $x = 4$ $x=4$

How do you solve e^lnx=4 elnx=4e^lnx=4 ?