How do you solve $e^{- x} = 6$ $e^-x=6$ ?

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Answer 1 · 2018-05-27T16:25:27

$x = - ln (6)$ $x=-ln(6)$

Taking the logarithm on both sides:
$- x = ln (6)$ $-x=ln(6)$
so
$x = - ln (6)$ $x=-ln(6)$

How do you solve e−x=6e^-x=6?