How do you solve for a in $(10ac-x)/ 11 = -3$ ?

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Answer 1 · 2016-02-17T05:37:47

This is just standard algebra, but the answer will be expressed in terms of $c$ and $x$ . See below for the full calculation. $a=(x-33)/(10c)$

Starting equation. Our goal is to get $a$ 'naked'. ;)

$(10ac-x)/11=-3$

Multiply both sides by 11:

$10ac-x=-33$

Add $x$ to both sides:

$10ac=x-33$

Divide both sides by $10c$ :

$a=(x-33)/(10c)$

And there's your answer.

How do you solve for a in (10ac-x)/ 11 = -3(10ac-x)/ 11 = -3?