How do you solve for A in $2A/3 = 8 + 4A$ ?

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Answer 1 · 2015-06-11T07:47:30

$color(red)(A = -18/11$

$2A/3 = 8 + 4A$

$2A/3$ is a mixed fraction
$= (6+A)/3$

Now the expression can be written as :
$(6+A)/3 = 8+4A$
$6+A = 3 xx (8+4A)$

$6+A = 24 + 12A$
$-18 = 11A$
$color(red)(A = -18/11$

How do you solve for A in 2A/3 = 8 + 4A2A/3 = 8 + 4A?