How do you solve for a in $ab=6+cd$ ?

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Answer 1 · 2018-03-04T18:22:37

See a solution process below:

Divide each side of the equation by $color(red)(b)$ to solve for $a$ while keeping the equation balanced:

$(ab)/color(red)(b) = (6 + cd)/color(red)(b)$

$(acolor(red)(cancel(color(black)(b))))/cancel(color(red)(b)) = (6 + cd)/b$

$a = (6 + cd)/b$

Or

$a = 6/b + (cd)/b$

How do you solve for a in ab=6+cdab=6+cd?