Question

How do you solve for A in `B=5/7(A-9)`?

Answer 1

See a solution process below:

Explanation:

First, multiply each side of the equation by `color(red)(7)/color(blue)(5)` to eliminate the need for parenthesis while keeping the equation balanced:

`color(red)(7)/color(blue)(5) xx B = color(red)(7)/color(blue)(5) xx 5/7(A - 9)`

`7/5B = cancel(color(red)(7))/cancel(color(blue)(5)) xx color(blue)(cancel(color(black)(5)))/color(red)(cancel(color(black)(7)))(A - 9)`

`7/5B = A - 9`

Now, add `color(red)(9)` to each side of the equation to solve for `A` while keeping the equation balanced:

`7/5B + color(red)(9) = A - 9 + color(red)(9)`

`7/5B + 9 = A - 0`

`7/5B + 9 = A`

`A = 7/5B + 9`