How do you solve for a: in $p = a + b + 3 c$ $p=a+b+3c$ ?

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Answer 1 · 2016-07-17T05:27:40

$a = p - b - 3 c$ $a=p-b-3c$

We start from the given equation
$p = a + b + 3 c$ $p=a+b+3c$

We are solving for $a$ $a$ . This means at the end of the math process, we should have $a =$ $a=$ to something.

$p = a + b + 3 c$ $p=a+b+3c$
By subtraction property of equality, subtract $b$ $b$ and $3 c$ $3c$ from both sides of the equation

$p - b - 3 c = a + b + 3 c - b - 3 c$ $p-b-3c=a+b+3c-b-3c$

$p - b - 3 c = a$ $p-b-3c=a$

and

$a = p - b - 3 c$ $a=p-b-3c$

God bless....I hope the explanation is useful.

How do you solve for a: in p=a+b+3cp=a+b+3cp=a+b+3c?