How do you solve for a in $sa=2ab+2ac+2bc$ ?

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Answer 1 · 2016-02-26T04:24:19

$a=(2bc)/(s-2b-2c)$

First, get all the terms with $a$ onto the same side of the equation.

Here, I'll subtract $2ab$ and $2ac$ from both sides of the equation so that all the terms with $a$ are on the left-hand side.

$sa-2ab-2ac=2bc$

Factor $a$ from every time on the right hand side.

$a(s-2b-2c)=2bc$

Divide both sides by $s-2b-2c$ .

$a=(2bc)/(s-2b-2c)$

This is as simplified as possible. Resist the urge to try to break apart the denominator--that's not allowed.

How do you solve for a in sa=2ab+2ac+2bc sa=2ab+2ac+2bc ?