How do you solve for a in $sqrt(a + 9)= b + 3$ ?

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Answer 1 · 2016-02-14T00:07:07

You must square both sides to move the 9 to the other side of the equation.

$sqrt(a + 9) = b + 3$

$(sqrt(a + 9))^2 = (b + 3)^2$

$a + 9 = b^2 + 6b + 9$

$a = b^2 + 6b or a = b(b + 6)$

Hopefully this helps!

How do you solve for a in sqrt(a + 9)= b + 3sqrt(a + 9)= b + 3?