How do you solve for b given $h = -16t^2 + b$ ?

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Answer 1 · 2017-04-14T13:58:41

See the solution process below:

Add $color(red)(16t^2)$ to each side of the equation to solve for $b$ while keeping the equation balanced:

$color(red)(16t^2) + h = color(red)(16t^2) - 16t^2 + b$

$16t^2 + h = 0 + b$

$16t^2 + h = b$

$b = 16t^2 + h$

How do you solve for b given h = -16t^2 + bh = -16t^2 + b?