How do you solve for b in $3ab–z = y(4ab +2z)$ ?

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Answer 1 · 2016-02-14T20:58:45

You must first distribute the parentheses.

$3ab - z = 4aby + 2yz$

Put the terms containing b on one side of the equation.

$3ab - 4aby = 2yz + z$

Factor out the b.

$b(3a - 4ay) = 2yz + z$

$b = (2yz + z)/(3a - 4ay)$ or $b = (z(2y + 1))/(a(3 - 4y))$

Practice exercises:

a) $(2x + 3y)/(4x - y) = (x + 3y)/(2x - 5y)$

b). $(2x + 3y + 2z) / x + (4x - 5y + 3z)/y = (x - 3y - 2z)/z$

Good luck!

How do you solve for b in 3ab–z = y(4ab +2z)3ab–z = y(4ab +2z)?