How do you solve for b in $A = 1/2h(B + b)$ ?

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Answer 1 · 2015-07-23T15:12:32

You isolate it on one side of the equation.

To solve your expression for $b$ , you need to isolate it on one side of the equation.

One way in which you can do that is by multiplying boths sides of the equation by 2 to get rid of the fraction.

$2 * A = cancel(2) * 1/cancel(2) * h(B + b)$

$2A = h(B + b)$

Now divide both sides of the equation by $h$ to get

$(2A)/h = cancel(h)/cancel(h) * (B + b)$

$(2A)/h = B + b$

Finally, move $B$ on the other side of the equation by subtracting it from both sides of the equation

$(2A)/h - B = cancel(B) - cancel(B) + b$

And there you have it, $b$ is equal to

$b = color(green)((2A)/h - B)$

How do you solve for b in A = 1/2h(B + b)A = 1/2h(B + b)?