How do you solve for B in $S=2B+Ph$ ?

Question

14979 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-07-05T20:58:58

See a solution process below:

First, subtract $color(red)(Ph)$ from each side of the equation to isolate the $B$ term while keeping the equation balanced:

$S - color(red)(Ph) = 2B + Ph - color(red)(Ph)$

$S - Ph = 2B + 0$

$S - Ph = 2B$

Now, divide each side of the equation by $color(red)(2)$ to solve for $B$ while keeping the equation balanced:

$(S - Ph)/color(red)(2) = (2B)/color(red)(2)$

$(S - Ph)/2 = (color(red)(cancel(color(black)(2)))B)/cancel(color(red)(2))$

$(S - Ph)/2 = B$

$B = (S - Ph)/2$

Or

$B = S/2 - (Ph)/2$

How do you solve for B in S=2B+PhS=2B+Ph?