How do you solve for c in $2a+3b+c=0$ ?

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Answer 1 · 2017-07-29T16:46:33

See a solution process below:

Subtract $color(red)(-(2a + 3b)$ from each side of the equation to solve for $c$ while keeping the equation balanced:

$2a + 3b - (2a + 3b) + c = 0 - (2a + 3b)$

$(2a + 3b) - (2a + 3b) + c = 0 - 2a - 3b$

$0 + c = -2a - 3b$

$c = -2a - 3b$

How do you solve for c in 2a+3b+c=0 2a+3b+c=0 ?