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How do you solve for c in $3 a b c + b = 5$ $3abc + b = 5$ ?

1 Answer

Feb 17, 2016

$c = \frac{5 - b}{3 a b}$ $c=(5-b)/(3ab)$

Explanation:

Given
$XXX 3 a b c + b = 5$ $color(white)("XXX")3abc+b=5$

Subtract $b$ $b$ from both sides:
$XXX 3 a b c = 5 - b$ $color(white)("XXX")3abc=5-b$
Divide both sides by $(3 a b)$ $(3ab)$
$XXX c = \frac{5 - b}{3 a b}$ $color(white)("XXX")c=(5-b)/(3ab)$

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