How do you solve for d in $cy-d=4d$ ?

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Answer 1 · 2016-03-06T05:26:30

$d=(cy)/5$

$cy-d=4d$

What we do on one side must be done on thee other side also
(Golden rule of algebra)

Add $d$ both sides

$rarrcy-d+d=4d+d$

$rarrcy=5d$

Divide both sides by $5$

$rarr(cy)/5=(cancel5d)/cancel5$

$rArrd=(cy)/5$

How do you solve for d in cy-d=4dcy-d=4d?