Question

How do you solve for d in `f=(Gm_1m_2)/d^2`?

Answer 1

`d=sqrt{(Gm_1m_2)/f}`

Explanation:

`f=(Gm_1m_2)/d^2`

`rArr d^2=(Gm_1m_2)/f`

`:. d=sqrt{(Gm_1m_2)/f}`