How do you solve for d in $f = \frac{G m_{1} m_{2}}{d^{2}}$ $f=(Gm_1m_2)/d^2$ ?

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Answer 1 · 2016-08-14T17:19:50

$d = \sqrt{\frac{G m_{1} m_{2}}{f}}$ $d=sqrt{(Gm_1m_2)/f}$

$f = \frac{G m_{1} m_{2}}{d^{2}}$ $f=(Gm_1m_2)/d^2$

$\Rightarrow d^{2} = \frac{G m_{1} m_{2}}{f}$ $rArr d^2=(Gm_1m_2)/f$

$:. d=sqrt{(Gm_1m_2)/f}$

How do you solve for d in f=(Gm_1m_2)/d^2 f=Gm1m2d2f=(Gm_1m_2)/d^2 ?