How do you solve for d in $n= (dh)/(f+d)$ ?

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Answer 1 · 2016-07-17T01:25:22

$color(green)((nf)/(h-n) = d)$

To solve for $d$ , we need to get it by itself (isolate the variable). First, undo the division by multiplying both sides by the denominator.

$n = (dh)/(f+d)$

$(f+d)/1 * n/1 = (dh)/cancel(f+d) * cancel(f+d)/1$

$((f+d)timesn) = dh$

$nf + nd = dh$

Now get all terms with $d$ to one side and factor out the $d$ .

$nf = dh-nd$

$nf = d(h-n)$

Finish isolating the variable by getting $d$ by itself.

$(nf)/(h-n) = (d(cancel(h-n)))/cancel(h-n)$

$color(green)((nf)/(h-n) = d)$

This is your final answer.

How do you solve for d in n= (dh)/(f+d)n= (dh)/(f+d)?