How do you solve for E in $V-E+F=2$ ?

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Answer 1 · 2017-01-21T22:15:00

See the entire solution process below:

First, subtract $color(red)(V)$ and $color(blue)(F)$ from each side of the equation to isolate the $E$ term while keeping the equation balanced:

$V - E + F - color(red)(V) - color(blue)(F) = 2 - color(red)(V) - color(blue)(F)$

$V - color(red)(V) - E + F - color(blue)(F) = 2 - color(red)(V) - color(blue)(F)$

$0 - E + 0 = 2 - V - F$

$-E = 2 - V - F$

Now, multiply each side of the equation by $color(red)(-1)$ to solve for $E$ while keeping the equation balanced:

$color(red)(-1) xx -E = color(red)(-1)(2 - V - F)$

$E = -2 + V + F$

How do you solve for E in V-E+F=2V-E+F=2?