Question

How do you solve for f in `C= 5/9 (f-32)`?

Answer 1

See solution below.

Explanation:

`C = 5/9(f - 32)`

`C/(f - 32) = 5/9`

Use the property `a/b = m/n -> a xx n = b xx m`

`9C = 5f - 160`

`9C + 160 = 5f`

`(9C + 160)/5= f`

`9/5C + 32 = f`

Practice exercises:

`1.` The formula for conversion between Celsius, `c` and farenheight `f`, is `C = 5/9(f - 32)`. Find how many farenheight would be 5 degrees Celsius.

`2.` Solve for x. Hint: try putting on the same denominator.

`1/x + 1/(xy) = 1/(x + y)`

Good luck!