How do you solve for F in $C=5/9(F-32)$ ?

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Answer 1 · 2016-05-09T22:01:33

$F = 9/5C+32$

Given:

$C = 5/9(F-32)$

First multiply both sides by $9/5$ to get:

$9/5C = F-32$

Add $32$ to both sides and transpose to get:

$F = 9/5C+32$

These are the formulas to translate between Fahrenheit and Celsius temperatures.

Fahrenheit and Celsius meet at $-40$ degrees.

That is $-40^@F = -40^@C$

So alternative formulas for the conversions can be written:

$F = 9/5(C+40)-40$

$C = 5/9(F+40)-40$

How do you solve for F in C=5/9(F-32)C=5/9(F-32)?