How do you solve for h in $12 h = 4 (2 h - 5)$ $12h=4(2h-5)$ ?

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How do you solve for h in $12 h = 4 (2 h - 5)$ $12h=4(2h-5)$ ?

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Answer 1 · 2016-11-20T17:52:45

$h = - 5$ $h=-5$

Explanation:

$" "$
$12 h = 4 (2 h - 5)$ $12h = 4(2h - 5)$
$" "$
$\Rightarrow 12 h = 8 h - 20$ $rArr12h = 8h - 20$
$" "$
$\Rightarrow 12 h - 8 h = - 20$ $rArr12h - 8h =-20$
$" "$
$\Rightarrow 4 h = - 20$ $rArr4h = -20$
$" "$
$\Rightarrow h = - \frac{20}{4}$ $rArr h=-20/4$
$" "$
$\Rightarrow h = - 5$ $rArrh = -5$

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How do you solve for h in $12 h = 4 (2 h - 5)$ $12h=4(2h-5)$ ?

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How do you solve for h in 12h=4(2h-5)12h=4(2h−5)12h=4(2h-5)?

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How do you solve for h in $12 h = 4 (2 h - 5)$ $12h=4(2h-5)$ ?