How do you solve for h: in $-3/7h = 6$ ?

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Answer 1 · 2016-05-02T11:06:23

$h=-42/3$

The objective is to get only one $h$ and for it to be on one side of the equals and everything else on the other side.

Multiply both sides by 7

$-(3h)/7 xx7=6xx7$

$-3hxx7/7=42$

But $7/7=1$ and anything multiplied by 1 does not change its inherent value.

$-3h=42$

Divide both sides by 3#

$-3/3xxh=42/3$

But $-3/3=-1$

$-h=42/3$

Multiply both sides by $(-1)$

$+h=-42/3$

How do you solve for h: in -3/7h = 6-3/7h = 6?