Question

How do you solve for h in `a=1/2bh`?

Answer 1

`b=(2a)/h`

Explanation:

rearrange by applying inverse operations.

`a=1/2bh`

multiply both sides by `2`

`2xxa=cancel(1/2xx2)bh`

`2a=bh`

divide both sides byb

`(2a)/h=bcancel(h/h)`

`b=(2a)/h`